7n+[3(1-n)-2(1+2)]=14

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Solution for 7n+[3(1-n)-2(1+2)]=14 equation:


Simplifying
7n + [3(1 + -1n) + -2(1 + 2)] = 14
7n + [(1 * 3 + -1n * 3) + -2(1 + 2)] = 14
7n + [(3 + -3n) + -2(1 + 2)] = 14

Combine like terms: 1 + 2 = 3
7n + [3 + -3n + -2(3)] = 14

Multiply -2 * 3
7n + [3 + -3n + -6] = 14

Reorder the terms:
7n + [3 + -6 + -3n] = 14

Combine like terms: 3 + -6 = -3
7n + [-3 + -3n] = 14

Remove brackets around [-3 + -3n]
7n + -3 + -3n = 14

Reorder the terms:
-3 + 7n + -3n = 14

Combine like terms: 7n + -3n = 4n
-3 + 4n = 14

Solving
-3 + 4n = 14

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 4n = 14 + 3

Combine like terms: -3 + 3 = 0
0 + 4n = 14 + 3
4n = 14 + 3

Combine like terms: 14 + 3 = 17
4n = 17

Divide each side by '4'.
n = 4.25

Simplifying
n = 4.25

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